 GET IT NOW x How to Design Bridge Footing and Its Pile Spacing?

• Example

In this example, we are designing a pile cap for a bridge. We have already calculated the forces at the top of the footing, but unclear of the footing dimensions along with the forces at its bottom face. Figure 1. Pile cap for a bridge.

The factored forces at the footing top are given as Pu= 4212 kips, Vu longitudinal = 108.4 kips, Vu transverse = 112.4 kips, Mu Longitudinal = 7340 ft-kips, Mu transverse = 16480 ft-kips.

Pile capacity is given as φRn = 424 kips/EA. Also, we never want any uplift for the piles.

Step 1) Figure 2. Preliminary dimension of the pile cap before iteration.

We have obtained these preliminary dimensions from engineering judgment or senior engineers' instinct.

Step 2) Calculating the forces at the footing bottom

Pu = 4212 kips + 1.25(31’-4”)(15’-9”){(0.150 kcf)(9’-0”) + (0.100kcf)(2’-0”)} = 5168 kips
M Long = (108.4 kips)(9’-0”) + 7340 ft-kips = 8316 ft-kips
M Trans = (112.4kips)(9’-0”) + 16480 ft-kips = 17492 ft-kips

Step 3) Find minimum required pile EA Try 6x4 = 24 EA, Figure 3. Pile locations.

Step 3)

Try transverse pile spacing x sps as 68”, which has been found from “Iteration” or “Optimization”.  Therefore, the longitudinal pile spacing y sps is selected as 51”.

Step 4)

The pile cap dimension is b = (6EA-1)(68”) + 2(1’-6”) = 31’-4”, h = (4EA-1)(51”) + 2(1’-6”)’ = 15’-9”, which match with the assumed value. Otherwise, we have to “Iterate”. Figure 4. Pile locations with X and Y spacings.

• What Are "Iteration" and "Optimization" in Pile Cap Design? Figure 5. Pile spacing vs Pile Cap Area (by program WSP USA-Pile)

The pile cap area from the dimensions obtained in Step 4 is (31’-4”) × (15’-9”) = 493.5 ft2

This graph shows the pile cap area and corresponding y sps for each value of x sps. We can see that the trial value of x sps = 68” is the one to produce the minimum pile cap area, in other words, it is the “Optimum”. This value of x sps has never been assumed or guessed, but it was calculated by “Iteration”.

From the graph, we can see that x sps = 5’-0” to 6’-6” range also gives a very economical pile cap area. Some engineers prefer equal spacing for both directions, and x sps = y sps = 5’-0” would be a good choice for them.

The engineer can decide pile spacings easily from this graph.

• Closure

Some engineers (including me) are obsessed with mathematical solutions and sometimes forget what is important. In the given figure, the x sps range 60” to 78” makes practically no difference, and trying to find the absolute minimum makes little sense. The engineer should try to determine the best pile spacing in the given range, rather than concentrate on small numbers.

We can solve this problem using the “Optimization” theory. We can ask the computer to find x sps and y sps which would give the minimum area of the pile cap, while the maximum reaction is less than φRn = 424 kips/EA
This methodology will be discussed later.

Here only the output from the “Optimization” theory is given: the “Optimum” pile cap dimension is x sps = 67.96”, y sps = 50.58”, and the pile cap area is 489.9 ft2., which is close to 493.5 ft2, we got from “Iteration”.

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